This question is good as it tests basic BJT temperature dependance understanding which, from an analog circuit design perspective, is very important as it is the basis of bandgap voltage reference design. As long as you know that , you’ll know that will decrease as temperature is increased.
Given the circuit below, what is ?
The answer is clearly since it’s just a basic current mirror. However, if you’re interviewing a co-op, they may have never been exposed to current mirrors or maybe they’re a bit rusty.
Given the circuit below, find :
This question is nice as it combines basic Op Amp and basic current mirror understanding. Since the input to the Op Amp is generated by a current mirror, we know that the current through is equivalent to . Hence, which means that . Since the inverting and non-inverting terminals of the amplifier will be equal, the voltage at the source of M3 will equal which means the current, , can be found by diving this voltage by the resistance at the source of M3. This yields the answer that .
What is the voltage gain of the following circuit?
This particular amplifier is a common-drain (or source-follower). Typically, the voltage gain is simply approximated to be equal to 1, but that’s not what we’re looking for here. We want the expression for the voltage gain- granted, with some reasonable assumptions, the expression IS approximately equal to 1 but let’s get the expression first, shall we? First, let’s draw the small-signal model:
Here we have a resistance, , in parallel with a dependent current source with a series resistance, . This means that the expression for the output voltage should be: Thus, the expression for the small-signal voltage gain is: